Which would be the first term of the given sequence that would be a multiple of 3: 68, 65, 62, 59 .... ?
Question
Which would be the first term of the given sequence that would be a multiple of 3:
68, 65, 62, 59 .... ?
Solution
The given sequence is a decreasing arithmetic sequence, where each term is 3 less than the previous term.
To find the first term that is a multiple of 3, we need to find a term in the sequence that can be divided by 3 with no remainder.
Starting with the first term, 68, we can see that it is not a multiple of 3.
The next term, 65, is also not a multiple of 3.
The third term, 62, is not a multiple of 3 either.
The fourth term, 59, is not a multiple of 3.
We continue this process until we find a term that is a multiple of 3.
The first term that is a multiple of 3 is 57.
So, the first term of the given sequence that would be a multiple of 3 is 57.
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