Find the z-score for the value 52, when the mean is 58 and the standard deviation is 9.Group of answer choicesz=-0.78z=-0.74z=0.74z=-0.67
Question
Find the z-score for the value 52, when the mean is 58 and the standard deviation is 9.
Group of answer choices
z = -0.78
z = -0.74
z = 0.74
z = -0.67
Solution
The z-score is calculated using the formula:
z = (X - μ) / σ
where: X is the value we are interested in (in this case, 52), μ is the mean (in this case, 58), and σ is the standard deviation (in this case, 9).
Substituting these values into the formula, we get:
z = (52 - 58) / 9 z = -6 / 9 z = -0.67
So, the z-score for the value 52, when the mean is 58 and the standard deviation is 9, is -0.67. Therefore, the correct answer is z=-0.67.
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