The average translational kinetic energy per molecule of an ideal gas at 0ºC (k =1.38 × 10–23 J/K)  is –

Question

The average translational kinetic energy per molecule of an ideal gas at 0ºC (k =1.38 × 10–23 J/K)  is –
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The average translational kinetic energy per molecule of an ideal gas is given by the equation:

KE_avg = 3/2 kT

where:

  • KE_avg is the average kinetic energy,
  • k is the Boltzmann constant (1.38 × 10–23 J/K), and
  • T is the temperature in Kelvin.

The temperature given is 0ºC, which is equivalent Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

The average translational kinetic energy per molecule of an ideal gas at 0ºC (k =1.38 × 10–23 J/K)  is –

What is the average kinetic energy per particle in 1.00 mole of an ideal gas at a pressure of 1.50 atmospheres and a volume of 2.00 liters?

For a substance, at 100oC the average speed and average kinetic energy of the particles is greater than at 0oC.Question 19Answera.Trueb.False

The initial kinetic energy of the system is K. The final kinetic energy of the system is K/n. What is the value of n?

Calculate the kinetic energy of a 400 kg horse running 6 m/s a2400 J b14400 J c4800 J d7200 J

1/3