True or False? In O, radius OP intersects chord AC in point B so that AB = 8 units and BC = 8 units. This means that OP is perpendicular to AC.A.TrueB.False
Question
True or False?
In circle O, radius OP intersects chord AC at point B such that:
- AB = 8 units
- BC = 8 units
This means that OP is perpendicular to AC.
A. True
B. False
Solution
Break Down the Problem
- Understand the relationship between the radius, the chord, and the perpendicularity.
- Analyze whether the given segments AB and BC being equal implies that the radius OP is perpendicular to chord AC.
Relevant Concepts
- A property of chords in circles states that if a radius drawn to a chord bisects the chord, then it is perpendicular to the chord.
- Given that AB = BC, chord AC is bisected by point B.
Analysis and Detail
- The lengths of AB and BC are equal (8 units each).
- Since B is the midpoint of AC, we conclude that chord AC is bisected by OP.
- According to the property mentioned above, if OP bisects AC, then it must indeed be perpendicular to AC.
Verify and Summarize
- OP bisects AC at point B where AB = BC.
- This confirms that OP is perpendicular to chord AC.
Final Answer
A. True
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