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Which would not have a heat of formation of 0 kJ/mol?   Group of answer choicesF2(g)H2(g)S2(g)Kr(g)

Question

Which would not have a heat of formation of 0 kJ/mol?

Group of answer choices

  • F2(g)
  • H2(g)
  • S2(g)
  • Kr(g)
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Solution

The heat of formation is defined as the heat absorbed or released when one mole of a substance is formed from its elements in their standard states. The standard state of an element is its most stable state at 1 atm and 25°C.

  1. F2(g): This is the standard state of Fluorine. So, its heat of formation is 0 kJ/mol.
  2. H2(g): This is the standard state of Hydrogen. So, its heat of formation is 0 kJ/mol.
  3. Kr(g): This is the standard state of Krypton. So, its heat of formation is 0 kJ/mol.

However,

  1. S2(g): This is not the standard state of Sulfur. The standard state of sulfur is S8(s). So, its heat of formation is not 0 kJ/mol.

Therefore, S2(g) would not have a heat of formation of 0 kJ/mol.

This problem has been solved

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