Which would not have a heat of formation of 0 kJ/mol? Group of answer choicesF2(g)H2(g)S2(g)Kr(g)
Question
Which would not have a heat of formation of 0 kJ/mol?
Group of answer choices
- F2(g)
- H2(g)
- S2(g)
- Kr(g)
Solution
The heat of formation is defined as the heat absorbed or released when one mole of a substance is formed from its elements in their standard states. The standard state of an element is its most stable state at 1 atm and 25°C.
- F2(g): This is the standard state of Fluorine. So, its heat of formation is 0 kJ/mol.
- H2(g): This is the standard state of Hydrogen. So, its heat of formation is 0 kJ/mol.
- Kr(g): This is the standard state of Krypton. So, its heat of formation is 0 kJ/mol.
However,
- S2(g): This is not the standard state of Sulfur. The standard state of sulfur is S8(s). So, its heat of formation is not 0 kJ/mol.
Therefore, S2(g) would not have a heat of formation of 0 kJ/mol.
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