An array-based implementation of a stack can be designed so that all stack operations are O(1). A. True B. False

The answer to the question is:

Final Answer

A. True

Explanation

In an array-based implementation of a stack, operations such as push, pop, and peek can be done in O(1) time complexity. This is achievable because:

1. Push Operation: You can add an element to the top of the stack by simply inserting it at the next available index in the array, which takes constant time.
2. Pop Operation: Removing the top element is also constant time since it involves accessing a specific index.
3. Peek Operation: Checking the top element is again just accessing an index in the array.

However, it is important to note that if the stack array exceeds its capacity, resizing the array (typically to double its current size) would take O(n) time. But in the average case, if we amortize the cost over a series of operations, the stack operations can still be considered O(1). Thus, the statement as interpreted is True.