To answer this question, we need to understand the law of universal gravitation, which states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

The formula for the gravitational force (F) between two masses (m1 and m2) separated by a distance (r) is:

F = G * (m1 * m2) / r^2

where G is the gravitational constant.

If the distance between the two masses is halved, the new distance is r/2. Substituting this into the formula gives:

F_new = G * (m1 * m2) / (r/2)^2
= G * (m1 * m2) / (r^2/4)
= 4 * G * (m1 * m2) / r^2
= 4 * F

So, the gravitational force in the new situation is four times the original force.

Question

To answer this question, we need to understand the law of universal gravitation, which states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

The formula for the gravitational force (F) between two masses (m1 and m2) separated by a distance (r) is:

F = G * (m1 * m2) / r^2

where G is the gravitational constant.

If the distance between the two masses is halved, the new distance is r/2. Substituting this into the formula gives:

F_new = G * (m1 * m2) / (r/2)^2
      = G * (m1 * m2) / (r^2/4)
      = 4 * G * (m1 * m2) / r^2
      = 4 * F

So, the gravitational force in the new situation is four times the original force.

Knowee AI · Accepted Answer

To answer this question, we need to understand the law of universal gravitation, which states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

The formula for the gravitational force (F) between two masses (m1 and m2) separated by a distance (r) is:

F = G * (m1 * m2) / r^2

where G is the gravitational constant.

If the distance between the two masses is halved, the new distance is r/2. Substituting this into the formula gives:

F_new = G * (m1 * m2) / (r/2)^2
      = G * (m1 * m2) / (r^2/4)
      = 4 * G * (m1 * m2) / r^2
      = 4 * F

So, the gravitational force in the new situation is four times the original force.

The distance between the two masses in the previous situation is halved. Determine the gravitational force in this new situation.

Question

The distance between the two masses in the previous situation is halved.

Solution

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