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Find the surface area of the sphere, to the nearest tenth. Use 3.14 for p. r = 6 m

Question

Find the surface area of the sphere, to the nearest tenth. Use 3.14 for π \pi . r=6 m r = 6 \ m

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Solution

1. Break Down the Problem

To find the surface area of a sphere, we will use the formula: A=4πr2 A = 4 \pi r^2 where AA is the surface area and rr is the radius of the sphere.

2. Relevant Concepts

In this case, we will substitute the given values into the formula. The radius rr is given as 6m6 \, \text{m} and we will use π3.14\pi \approx 3.14.

3. Analysis and Detail

Now, we will substitute the values into the formula and perform the calculations:

  1. Calculate r2r^2: r2=62=36 r^2 = 6^2 = 36

  2. Calculate 4πr24 \pi r^2: A=4×3.14×36 A = 4 \times 3.14 \times 36

    Calculating 4×3.144 \times 3.14: 4×3.14=12.56 4 \times 3.14 = 12.56

    Now, multiply this result by 3636: A=12.56×36=452.16 A = 12.56 \times 36 = 452.16

4. Verify and Summarize

The calculated surface area of the sphere is 452.16m2452.16 \, \text{m}^2. Rounding this to the nearest tenth gives us 452.2m2452.2 \, \text{m}^2.

Final Answer

The surface area of the sphere is 452.2m2452.2 \, \text{m}^2.

This problem has been solved

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