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The area (in sq. units) of an equilateral triangle inscribed in the parabola y2 = 8x, with one of its vertices on the vertex of this parabola, is :

Question

The area (in sq. units) of an equilateral triangle inscribed in the parabola y2=8x y^2 = 8x , with one of its vertices on the vertex of this parabola, is :

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Solution

To find the area of an equilateral triangle inscribed in the parabola y^2 = 8x, with one of its vertices on the vertex of the parabola, we can follow these steps:

Step 1: Determine the coordinates of the vertex of the parabola. The given equation y^2 = 8x represents a parabola with its vertex at the origin (0, 0).

Step 2: Find the coordinates of one of the vertices of the equilateral triangle. Since one of the vertices of the equilateral triangle is on the vertex of the parabola, we can take the vertex of the parabola as one of the vertices of the triangle. Therefore, one of the vertices of the equilateral triangle is (0, 0).

Step 3: Find the coordinates of the other two vertices of the equilateral triangle. To find the other two vertices, we need to consider the properties of an equilateral triangle. Since all sides of an equilateral triangle are equal, we can determine the length of one side by finding the distance between the vertex of the parabola and any other point on the parabola.

Let's consider a point (x, y) on the parabola. The distance between this point and the vertex of the parabola is given by the formula: distance = sqrt((x - 0)^2 + (y - 0)^2) = sqrt(x^2 + y^2)

Since the triangle is equilateral, the distance between any two vertices is equal to the length of one side. Therefore, the distance between the vertex of the parabola and any other point on the parabola is equal to the length of one side of the equilateral triangle.

Step 4: Find the length of one side of the equilateral triangle. To find the length of one side, we need to find the distance between the vertex of the parabola and any other point on the parabola. Let's consider a point (x, y) on the parabola.

Substituting y^2 = 8x into the distance formula, we have: distance = sqrt(x^2 + (8x)^2) = sqrt(x^2 + 64x^2) = sqrt(65x^2) = sqrt(65)x

Since the distance between the vertex of the parabola and any other point on the parabola is equal to the length of one side of the equilateral triangle, we have: length of one side = sqrt(65)x

Step 5: Find the area of the equilateral triangle. The area of an equilateral triangle can be calculated using the formula: area = (sqrt(3)/4) * (length of one side)^2

Substituting the length of one side from Step 4 into the formula, we have: area = (sqrt(3)/4) * (sqrt(65)x)^2 = (sqrt(3)/4) * 65x = (65sqrt(3)/4) * x

Therefore, the area of the equilateral triangle inscribed in the parabola y^2 = 8x, with one of its vertices on the vertex of the parabola, is (65sqrt(3)/4) * x square units.

This problem has been solved

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