The half life of 26Na is 1.077 seconds. What is the decay constant for 26Na?k = ln(2) / t1/2Give your answer in s-1 and to three decimal places.
Question
The half life of 26Na is 1.077 seconds. What is the decay constant for 26Na?
Give your answer in s<sup>-1</sup> and to three decimal places.
Solution
The decay constant (k) for a radioactive substance can be calculated using the formula:
k = ln(2) / t1/2
where: ln(2) is the natural logarithm of 2, t1/2 is the half-life of the substance.
Given that the half-life (t1/2) of 26Na is 1.077 seconds, we can substitute this value into the formula to find the decay constant:
k = ln(2) / 1.077
Using a calculator to find the natural logarithm of 2 (approximately 0.693), the equation becomes:
k = 0.693 / 1.077
Solving for k gives a value of approximately 0.643 s^-1.
So, the decay constant for 26Na is approximately 0.643 s^-1 to three decimal places.
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