The half life of 26Na is 1.077 seconds. What is the decay constant for 26Na?k = ln(2) / t1/2Give your answer in s-1 and to three decimal places.

Question

The half life of 26Na is 1.077 seconds. What is the decay constant for 26Na?k = ln(2) / t1/2Give your answer in s-1 and to three decimal places.
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

The decay constant (k) for a radioactive substance can be calculated using the formula:

k = ln(2) / t1/2

where: ln(2) is the natural logarithm of 2, t1/2 is the half-life of the substance.

Given that the half-life (t1/2) of 26Na is 1.077 seconds, we can substitute this value into the formula to f Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

The half life of 26Na is 1.077 seconds. What is the decay constant for 26Na?k = ln(2) / t1/2Give your answer in s-1 and to three decimal places.

A first-order reaction has a half-life of 20 seconds. Calculate the rate constant for this reaction. GIve your answer to 3 decimal places.

Express the logarithm ln(9)=2.19722 (to 5 decimal places) in its exponential form

Use a calculator to find the value to four decimal places. (If an answer is undefined, enter UNDEFINED.)ln 0.666

In a first-order reaction A B , if k is the rate constant and initial concentration of thereactant A is 0.5 M, then the half-life i

1/3