Calculate the resistance of a 5 m Constantine wire of cross-sectional area of 3.5π x 10^-8 m^2 and resistivity of 1.1 x 10^-6 Ωm*1 point20 Ω50 Ω0.02 Ω0.05 Ω
Question
Calculate the resistance of a 5 m Constantine wire of cross-sectional area of 3.5π x 10^-8 m^2 and resistivity of 1.1 x 10^-6 Ωm
1 point
20 Ω
50 Ω
0.02 Ω
0.05 Ω
Solution
The resistance (R) of a wire can be calculated using the formula:
R = ρL/A
where: ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire.
Given: ρ = 1.1 x 10^-6 Ωm, L = 5 m, and A = 3.5π x 10^-8 m^2.
Substituting these values into the formula gives:
R = (1.1 x 10^-6 Ωm * 5 m) / (3.5π x 10^-8 m^2)
Solving this equation gives:
R = 0.05 Ω
So, the resistance of the wire is 0.05 Ω.
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