The greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is found by subtracting 6 from each number and then finding the greatest common divisor (GCD) of the results.

Step 1: Subtract 6 from each number
48 - 6 = 42
97 - 6 = 91
188 - 6 = 182

Step 2: Find the GCD of 42, 91, and 182
The GCD of 42, 91, and 182 is 7.

So, the greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is 7. Therefore, the answer is B.7.

Question

The greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is found by subtracting 6 from each number and then finding the greatest common divisor (GCD) of the results.

Step 1: Subtract 6 from each number
48 - 6 = 42
97 - 6 = 91
188 - 6 = 182

Step 2: Find the GCD of 42, 91, and 182
The GCD of 42, 91, and 182 is 7.

So, the greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is 7. Therefore, the answer is B.7.

Knowee AI · Accepted Answer

The greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is found by subtracting 6 from each number and then finding the greatest common divisor (GCD) of the results.

Step 1: Subtract 6 from each number
48 - 6 = 42
97 - 6 = 91
188 - 6 = 182

Step 2: Find the GCD of 42, 91, and 182
The GCD of 42, 91, and 182 is 7.

So, the greatest number that will divide 48, 97, and 188 and leaves the remainder 6 in each case is 7. Therefore, the answer is B.7.

Find the greatest number that will divide 48, 97 and 188 and leaves the reminder 6 in each case.Options :A.4B.7C.2D.6

Question

Find the greatest number that will divide 48, 97 and 188 and leaves the reminder 6 in each case.

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