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A rectangular building has an area of 1512 square metres. Its perimeter is 164 metres. What are the dimensions of the building?

Question

A rectangular building has an area of 1512 square metres.

Its perimeter is 164 metres.

What are the dimensions of the building?

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Solution

To find the dimensions of the building, we can use the formulas for the area and perimeter of a rectangle.

The area (A) of a rectangle is given by the formula A = length * width. We know that the area is 1512 square metres.

The perimeter (P) of a rectangle is given by the formula P = 2 * (length + width). We know that the perimeter is 164 metres.

Let's denote the length of the rectangle as L and the width as W.

From the area formula, we have:

  1. L * W = 1512

From the perimeter formula, we have:

  1. 2 * (L + W) = 164 which simplifies to: L + W = 82

Now we have a system of two equations, and we can solve it step by step.

First, let's express L from the second equation:

L = 82 - W

Now we can substitute L from this equation into the first one:

(82 - W) * W = 1512

This is a quadratic equation. Solving it gives us the possible values for W:

W = 36 or W = 46

Substituting these values back into the equation L = 82 - W gives us the corresponding lengths:

L = 46 or L = 36

So, the dimensions of the building are 36 metres by 46 metres.

This problem has been solved

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