Given the following 8-bit integer binary variables: X1 = 11000110X2 = 11110111 What is the value in X3 after the following command? ADD X3, X2, X1

First, let's convert the binary numbers to decimal to make the addition easier.

X1 = 11000110 = 198 in decimal X2 = 11110111 = 247 in decimal

The ADD command adds X2 and X1 and stores the result in X3. So,

X3 = X2 + X1 X3 = 247 + 198 X3 = 445

However, since we're dealing with 8-bit integers, the range of values we can represent is from 0 to 255. If a calculation results in a number outside this range, it will "wrap around" from the start or end of this range. This is known as overflow.

So, to find the value that X3 would actually hold, we subtract the maximum value (255) plus 1 from the result:

X3 = 445 - (255 + 1) X3 = 445 - 256 X3 = 189

So, X3 would hold the value 189. To convert this back to binary:

X3 = 189 = 10111101 in binary.