. Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245g mol-1.

To calculate the mass of sodium acetate required, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters

We can rearrange this formula to find the moles of solute:

moles of solute = Molarity (M) * volume of solution in liters

We know that the molarity is 0.375 M and the volume of the solution is 500 mL or 0.5 L. So,

moles of solute = 0.375 M * 0.5 L = 0.1875 mol

Now, we can find the mass of the sodium acetate by multiplying the moles of solute by the molar mass of sodium acetate:

mass of sodium acetate = moles of solute * molar mass of sodium acetate

mass of sodium acetate = 0.1875 mol * 82.0245 g/mol = 15.38 g

So, you would need approximately 15.38 g of sodium acetate to make a 500 mL of 0.375 M aqueous solution.