To determine if z[n] is a causal system, we need to analyze its properties. A system is considered causal if the output at any given time depends only on the current and past inputs, and not on future inputs.

In this case, z[n] is defined as the sum of z[n-1] and y[n]. Since z[n] depends on z[n-1], which is the previous output, it implies that z[n] does depend on past values of the system. However, y[n] is defined as nx[n] – (n-1)x[n], where n is the current time index.

Since y[n] includes the current time index n, it means that the output z[n] also depends on the current time index. This indicates that z[n] is not solely determined by past inputs, violating the causality condition.

Therefore, the answer is 2. No, z[n] is not a causal system.

Question

To determine if z[n] is a causal system, we need to analyze its properties. A system is considered causal if the output at any given time depends only on the current and past inputs, and not on future inputs.

In this case, z[n] is defined as the sum of z[n-1] and y[n]. Since z[n] depends on z[n-1], which is the previous output, it implies that z[n] does depend on past values of the system. However, y[n] is defined as nx[n] – (n-1)x[n], where n is the current time index.

Since y[n] includes the current time index n, it means that the output z[n] also depends on the current time index. This indicates that z[n] is not solely determined by past inputs, violating the causality condition.

Therefore, the answer is 2. No, z[n] is not a causal system.

Knowee AI · Accepted Answer

To determine if z[n] is a causal system, we need to analyze its properties. A system is considered causal if the output at any given time depends only on the current and past inputs, and not on future inputs.

In this case, z[n] is defined as the sum of z[n-1] and y[n]. Since z[n] depends on z[n-1], which is the previous output, it implies that z[n] does depend on past values of the system. However, y[n] is defined as nx[n] – (n-1)x[n], where n is the current time index.

Since y[n] includes the current time index n, it means that the output z[n] also depends on the current time index. This indicates that z[n] is not solely determined by past inputs, violating the causality condition.

Therefore, the answer is 2. No, z[n] is not a causal system.

We define y[n] = nx[n] – (n-1)x[n]. Now, z[n] = z[n-1] + y[n]. Is z[n] a causal system?Select one:1. Yes2. No

Question

We define $y[n] = nx[n] – (n-1)x[n]$ . Now, $z[n] = z[n-1] + y[n]$ . Is z[n] a causal system?

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