A rectangular lot is 60 meters wide and 105 meters long.Give the length and width of another rectangular lot that has the same perimeter but a smaller area.

To solve this problem, we first need to understand the relationship between the perimeter and area of a rectangle.

The perimeter of a rectangle is calculated as 2*(length + width). In this case, the perimeter of the given lot is 2*(60m + 105m) = 330m.

The area of a rectangle is calculated as length * width. In this case, the area of the given lot is 60m * 105m = 6300m^2.

We are asked to find the dimensions of another rectangular lot that has the same perimeter (330m) but a smaller area. This means we need to find a length and width that when added together equal 165m (since 2*165m = 330m), but when multiplied together give a value less than 6300m^2.

One way to do this is to make the length and width more equal. The more equal the length and width of a rectangle, the larger the area for a given perimeter. So, to make the area smaller, we should make the length and width less equal.

For example, if we make the width 70m and the length 95m, the perimeter is still 330m (since 2*(70m + 95m) = 330m), but the area is now 70m * 95m = 6650m^2, which is smaller than the area of the given lot.

So, a rectangular lot that is 70 meters wide and 95 meters long has the same perimeter but a smaller area than the given lot.