The volume V of a cone is given by the formula V = 1/3 * π * r² * h, where r is the radius and h is the height.

In this case, we are given a cone with radius 2 and height 6, but we are only filling it up to height 3.

Since the height is halved, the volume will also be halved.

So, the volume of the water in the cone would be 1/2 * (1/3 * π * 2² * 6) = 1/2 * (4/3 * π * 6) = 4π cubic units.

Question

The volume V of a cone is given by the formula V = 1/3 * π * r² * h, where r is the radius and h is the height.

In this case, we are given a cone with radius 2 and height 6, but we are only filling it up to height 3.

Since the height is halved, the volume will also be halved.

So, the volume of the water in the cone would be 1/2 * (1/3 * π * 2² * 6) = 1/2 * (4/3 * π * 6) = 4π cubic units.

Knowee AI · Accepted Answer

The volume V of a cone is given by the formula V = 1/3 * π * r² * h, where r is the radius and h is the height.

In this case, we are given a cone with radius 2 and height 6, but we are only filling it up to height 3.

Since the height is halved, the volume will also be halved.

So, the volume of the water in the cone would be 1/2 * (1/3 * π * 2² * 6) = 1/2 * (4/3 * π * 6) = 4π cubic units.

We have a cone with radius 2 and height 6. We are filling it with water. What would be the volume of water if we fill it up to height 3?