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What is the output of the following code.l = [‘Logik', ‘works'] for i in l:     i.swapcase() print(l)

Question

What is the output of the following code.

l = [‘Logik', ‘works']  
for i in l:  
    i.swapcase()  
print(l)
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Solution

The output of the code will be the same as the original list: ['Logik', 'works']

Here's why:

  1. The list l is defined with two strings: 'Logik' and 'works'.
  2. The for loop iterates over each item in the list. For each item, it calls the swapcase() method, which swaps the case of each letter in the string (i.e., it makes uppercase letters lowercase and vice versa). However, this doesn't actually change the original list because strings in Python are immutable, meaning they can't be changed after they're created. The swapcase() method returns a new string and doesn't modify the original string.
  3. Finally, the print(l) statement prints the original list, which hasn't been changed by the for loop.

If you want to change the original list, you need to create a new list to store the results, like this:

l = ['Logik', 'works']
new_l = []
for i in l:
    new_l.append(i.swapcase())
print(new_l)

This will output: ['lOGIK', 'WORKS']

This problem has been solved

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