There are 9 teachers in a group. 3 of them will be chosen to turn out the final paper. How many possible outcomes are there for the team members.
Question
There are 9 teachers in a group. 3 of them will be chosen to turn out the final paper. How many possible outcomes are there for the team members?
Solution
This is a combination problem. The number of ways to choose k items from a group of n items is given by the combination formula:
C(n, k) = n! / [k!(n-k)!]
where:
- n is the total number of items
- k is the number of items to choose
- "!" denotes factorial, which is the product of all positive integers up to that number
We need to choose 3 teachers out of 9. So, we calculate the number of combinations:
C(9, 3) = 9! / [3!(9-3)!] = 84
So, there are 84 possible outcomes for the team members.
Similar Questions
There are twelve students in a group, they want to choose three people at random for the speech contest, how many different three-people groups are possible?
From a group of 9 people, select the best 3 players to represent the group to participate in the team competition. How many total possibilities are there?
If the Math Olympiad Club consists of 12 students, how many different teams of 3 students can be formed for competitions?
There were 9 students running in a race. How many different arrangements of first, second, and third place are possible?
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.