Let ABCD be a square such that |AB|=6,|BC=4||AD|=10,∠ACD=90∘ and ∠ABC=120∘. Find sin(∠CAD).
Question
Let ABCD be a square such that
- |AB|=6,
- |BC|=4
- |AD|=10,
- ∠ACD=90∘
- ∠ABC=120∘.
Find sin(∠CAD).
Solution
1. Break Down the Problem
We have a figure ABCD that contains a square and a triangle. Given the lengths of the sides and angles, we need to find .
2. Relevant Concepts
- Use the sine rule and properties of the triangle to find the unknown angle.
- In the context of triangle geometry:
- The Law of Cosines may also be relevant due to the angles involved.
3. Analysis and Detail
-
Given the properties of square , we know: However, this conflicts with given segments of and . Thus, it seems we need to interpret a more general quadrilateral scenario instead of strictly confining to a square.
-
Since (a right angle), triangle can be analyzed using the Pythagorean theorem: where and . However, .
-
Next, analyze triangle :
-
Using the Law of Sines in triangle : With and , we can now solve for .
4. Verify and Summarize
Apply the law of sines: which gives us: thus, However, sine values cannot exceed 1, so there must have been a mistake in our assumptions.
Revisit: must be adjusted with triangle constraints from .
Final Answer
Let’s derive through a correct setup:
- indicates an error in interpretation or assumptions about the triangle. Verify all steps and side relationships in correction: ensure physical existence of triangles.
Please confirm the relationships you’re using or clarify dimensions, as typical sine values range should reflect.
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