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Let ABCD be a square such that |AB|=6,|BC=4||AD|=10,∠ACD=90∘ and ∠ABC=120∘. Find sin(∠CAD).

Question

Let ABCD be a square such that

  • |AB|=6,
  • |BC|=4
  • |AD|=10,
  • ∠ACD=90∘
  • ∠ABC=120∘.

Find sin(∠CAD).

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Solution

1. Break Down the Problem

We have a figure ABCD that contains a square and a triangle. Given the lengths of the sides and angles, we need to find sin(CAD)\sin(\angle CAD).

2. Relevant Concepts

  • Use the sine rule and properties of the triangle to find the unknown angle.
  • In the context of triangle geometry:
    • sin(θ)=oppositehypotenuse\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}
    • The Law of Cosines may also be relevant due to the angles involved.

3. Analysis and Detail

  1. Given the properties of square ABCDABCD, we know: AB=BC=CD=DA=6 |AB| = |BC| = |CD| = |DA| = 6 However, this conflicts with given segments of BC=4BC = 4 and AD=10AD = 10. Thus, it seems we need to interpret a more general quadrilateral scenario instead of strictly confining to a square.

  2. Since ACD=90\angle ACD = 90^\circ (a right angle), triangle ACDACD can be analyzed using the Pythagorean theorem: AD2=AC2+CD2 |AD|^2 = |AC|^2 + |CD|^2 where AD=10AD = 10 and CD=6CD = 6. However, AC=10262=10036=64=8AC = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8.

  3. Next, analyze triangle ABCABC: Using ABC=120, hence AC can be affected by ABC. \text{Using } \angle ABC = 120^\circ, \text{ hence } |AC| \text{ can be affected by } \angle ABC.

  4. Using the Law of Sines in triangle ACDACD: ADsin(CAD)=ACsin(ACD). \frac{|AD|}{\sin(\angle CAD)} = \frac{|AC|}{\sin(\angle ACD)}. With AD=10|AD| = 10 and AC=8|AC| = 8, we can now solve for sin(CAD)\sin(\angle CAD).

4. Verify and Summarize

Apply the law of sines: 10sin(CAD)=8sin(90) \frac{10}{\sin(\angle CAD)} = \frac{8}{\sin(90^\circ)} which gives us: 10sin(CAD)=8, \frac{10}{\sin(\angle CAD)} = 8, thus, sin(CAD)=108=1.25. \sin(\angle CAD) = \frac{10}{8} = 1.25. However, sine values cannot exceed 1, so there must have been a mistake in our assumptions.

Revisit: CAD\angle CAD must be adjusted with triangle constraints from ABC\angle ABC.

Final Answer

Let’s derive sin(CAD)\sin(\angle CAD) through a correct setup:

  1. sin(CAD)=1.25\sin(\angle CAD) = 1.25 indicates an error in interpretation or assumptions about the triangle. Verify all steps and side relationships in correction: ensure physical existence of triangles.

Please confirm the relationships you’re using or clarify dimensions, as typical sine values range should reflect.

This problem has been solved

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