The pair of species having same percentage of carbon is CH3COOH and C6H12O6        CH3COOH and C2H5OHHCOOCH3 and C12H22O11        C6H12O6 and C12H22O11

To determine which pair of species has the same percentage of carbon, we can calculate the percentage of carbon in each compound. Let's break down the calculations for each pair of species.

1. Breakdown the Problem

We need to find the percentage of carbon for each compound in the pairs to see if any pairs share the same percentage.

2. Relevant Concepts

The percentage of an element in a compound can be calculated using the formula: $\text{Percentage of Carbon} = \left( \frac{\text{Mass of Carbon in the formula}}{\text{Molar Mass of the compound}} \right) \times 100$

3. Analysis and Detail

a. For CH₃COOH (Acetic Acid)

• Molar Mass: $12.01 \times 2 + 1.008 \times 4 + 16.00 \times 2 = 60.05 \, \text{g/mol}$
• Mass of Carbon: $12.01 \times 2 = 24.02 \, \text{g/mol}$ $\text{Percentage of Carbon} = \left( \frac{24.02}{60.05} \right) \times 100 \approx 39.94\%$

b. For C₆H₁₂O₆ (Glucose)

• Molar Mass: $12.01 \times 6 + 1.008 \times 12 + 16.00 \times 6 = 180.18 \, \text{g/mol}$
• Mass of Carbon: $12.01 \times 6 = 72.06 \, \text{g/mol}$ $\text{Percentage of Carbon} = \left( \frac{72.06}{180.18} \right) \times 100 \approx 40.00\%$

c. For C₂H₅OH (Ethanol)

• Molar Mass: $12.01 \times 2 + 1.008 \times 6 + 16.00 = 46.07 \, \text{g/mol}$
• Mass of Carbon: $12.01 \times 2 = 24.02 \, \text{g/mol}$ $\text{Percentage of Carbon} = \left( \frac{24.02}{46.07} \right) \times 100 \approx 52.14\%$

d. For HCOOCH₃ (Methyl Formate)

• Molar Mass: $12.01 \times 2 + 1.008 \times 4 + 16.00 = 60.05 \, \text{g/mol}$
• Mass of Carbon: $12.01 \times 2 = 24.02 \, \text{g/mol}$ $\text{Percentage of Carbon} = \left( \frac{24.02}{60.05} \right) \times 100 \approx 39.94\%$

e. For C₁₂H₂₂O₁₁ (Sucrose)

• Molar Mass: $12.01 \times 12 + 1.008 \times 22 + 16.00 \times 11 = 342.30 \, \text{g/mol}$
• Mass of Carbon: $12.01 \times 12 = 144.12 \, \text{g/mol}$ $\text{Percentage of Carbon} = \left( \frac{144.12}{342.30} \right) \times 100 \approx 42.09\%$

4. Verify and Summarize

• CH₃COOH: 39.94%
• C₆H₁₂O₆: 40.00%
• C₂H₅OH: 52.14%
• HCOOCH₃: 39.94%
• C₁₂H₂₂O₁₁: 42.09%

Final Answer

The pairs that have the same percentage of carbon are: CH₃COOH and HCOOCH₃, both approximately 39.94%.