A number greater than 32 would require a minimum of how may bits in binary representation?  56410

The question seems to be a bit unclear, but if you're asking about the minimum number of bits required to represent a number greater than 32 in binary, here's how you can calculate it:

1. First, find the next power of 2 that is greater than 32. That would be 64 (2^6).

2. The power to which 2 is raised (in this case, 6) is the minimum number of bits required to represent numbers up to that power of 2. However, since we want to represent a number greater than 32, we need an additional bit.

3. Therefore, a number greater than 32 would require a minimum of 7 bits in binary representation.

If you're asking about the binary representation of the number 56410, here's how you can calculate it:

1. Convert the decimal number to binary. The binary representation of 56410 is 1101110000011010.

2. Count the number of bits in the binary representation. In this case, the binary representation of 56410 has 16 bits.