SELECT round(sum(item_count*order_occurrences)/sum(order_occurrences),1) as meanFROM items_per_order
Question
SELECT round(sum(item_count*order_occurrences)/sum(order_occurrences),1) as mean
FROM items_per_order
Solution
This SQL query is calculating the average number of items per order. Here's how it works:
-
item_count*order_occurrences
: This part of the query multiplies the number of items in an order by the number of times that order occurred. It does this for each row in theitems_per_order
table. -
sum(item_count*order_occurrences)
: This sums up the results of the above operation for all rows in the table. This gives us the total number of items ordered. -
sum(order_occurrences)
: This sums up the number of times each order occurred. This gives us the total number of orders. -
sum(item_count*order_occurrences)/sum(order_occurrences)
: This divides the total number of items ordered by the total number of orders. This gives us the average
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