A is twice as good a workman as B and together they finish a piece of work in 14 days. A alone can finish the work in:
Question
A is twice as good a workman as B and together they finish a piece of work in 14 days. A alone can finish the work in:
Solution
Let's solve this step by step:
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Let's assume the amount of work to be done is 1 unit.
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Let's say B takes x days to complete the work alone.
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Since A is twice as good a workman as B, A will take x/2 days to complete the work alone.
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If A and B work together, they can complete 1/x + 2/x = 3/x of the work in a day.
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But we know that A and B together can finish the work in 14 days. So, 3/x = 1/14.
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Solving for x, we get x = 42. This means B alone would take 42 days to finish the work.
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Since A is twice as efficient as B, A alone would take 42/2 = 21 days to finish the work.
So, A alone can finish the work in 21 days.
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