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A student has time to visit 3 of their 6 favorite colleges. How many different ways can the visits be arranged? 20 18 720 120

Question

A student has time to visit 3 of their 6 favorite colleges. How many different ways can the visits be arranged?

Options:

  • 20
  • 18
  • 720
  • 120
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Solution

This is a problem of permutations. The student has 6 colleges to choose from and wants to visit 3 of them. The order in which the colleges are visited matters, so we use the formula for permutations:

P(n, r) = n! / (n-r)!

where n is the total number of options (6 colleges), r is the number of options chosen at a time (3 colleges), and "!" denotes factorial.

Step 1: Calculate n! = 6! = 65432*1 = 720

Step 2: Calculate (n-r)! = (6-3)! = 3! = 321 = 6

Step 3: Substitute these values into the formula: P(6, 3) = 720 / 6 = 120

So, there are 120 different ways the student can arrange visits to 3 of their 6 favorite colleges.

This problem has been solved

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