If y is inversely proportional to x3, and y = 8 when x = 2,what is the value of y when x = 4?y =
Question
If y is inversely proportional to x<sup>3</sup>, and y = 8 when x = 2, what is the value of y when x = 4?
y =
Solution
If y is inversely proportional to x³, it means that the product of y and x³ is a constant. We can express this relationship as y = k/(x³), where k is the constant of variation.
Given that y = 8 when x = 2, we can find the value of k by substituting these values into the equation:
8 = k/(2³) 8 = k/8 k = 8 * 8 = 64
Now that we know k = 64, we can find the value of y when x = 4:
y = 64/(4³) y = 64/64 y = 1
So, the value of y when x = 4 is 1.
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