A reaction has the rate law:Rate = k[NO] 2 [H 2 ].If [NO] and [H 2 ] are both increased by a factor of 3, what will be the observed changein the rate?
Question
A reaction has the rate law:
Rate = k[NO] ^ 2 [H2]
If [NO] and [H2] are both increased by a factor of 3, what will be the observed change in the rate?
Solution
The rate law is given as Rate = k[NO]^2 [H2]. This means that the rate of the reaction is directly proportional to the square of the concentration of NO and the concentration of H2.
If both [NO] and [H2] are increased by a factor of 3, we substitute these into the rate law:
New Rate = k(3[NO])^2 * (3[H2])
This simplifies to:
New Rate = k * 9[NO]^2 * 3[H2]
So, the new rate is 27 times the original rate. Therefore, the observed change in the rate will be an increase by a factor of 27.
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