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i) if we toss this coin 88   times, then the probability of getting 66   or more heads  (to two decimal places) is .

Question

i)

If we toss this coin 88 times, then the probability of getting 66 or more heads (to two decimal places) is.

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Solution

To calculate the probability of getting 66 or more heads when tossing a coin 88 times, we need to use the binomial probability formula.

The binomial probability formula is:

P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))

where:

  • P(X=k) is the probability of k successes in n trials
  • C(n, k) is the combination of n items taken k at a time
  • p is the probability of success on a single trial (0.5 for a fair coin)
  • n is the number of trials
  • k is the number of successes

However, we want the probability of getting 66 or more heads. This means we need to calculate the probability for each possible number of heads from 66 to 88 and then add those probabilities together.

This calculation can be quite complex and is typically done using statistical software or a scientific calculator with statistical functions.

Please note that the probability of getting 66 or more heads in 88 tosses of a fair coin is quite low, as this is a significantly higher number of heads than would be expected based on the 50/50 odds of a fair coin.

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