If 3 dices are rolled, what is the probability of getting sum of the values on them is 11?Question 18Answera.31/216b.9/216c.27/216d.13/216

To solve this problem, we need to find all the possible outcomes that sum up to 11 when three dice are rolled.

1. (2,3,6), (2,4,5), (2,5,4), (2,6,3), (3,2,6), (3,3,5), (3,4,4), (3,5,3), (3,6,2), (4,2,5), (4,3,4), (4,4,3), (4,5,2), (5,2,4), (5,3,3), (5,4,2), (6,2,3), (6,3,2)
2. Each of these 18 outcomes can occur in 3! = 6 ways (since the three dice are distinct), so there are 18*6 = 108 successful outcomes.

The total number of outcomes when three dice are rolled is 6^3 = 216.

So, the probability of getting a sum of 11 when three dice are rolled is 108/216 = 0.5 or 1/2.

However, none of the options provided (a.31/216, b.9/216, c.27/216, d.13/216) match this result. There might be a mistake in the question or the provided options.