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A light ray strikes a mirror at an angle of 56o to the normal. Find the angle between the incident ray and the reflected ray.

Question

A light ray strikes a mirror at an angle of 56° to the normal. Find the angle between the incident ray and the reflected ray.

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Solution

1. Break Down the Problem

To find the angle between the incident ray and the reflected ray:

  1. Identify the angle of incidence.
  2. Apply the law of reflection, which states that the angle of reflection is equal to the angle of incidence.
  3. Determine the angle between the incident ray and the reflected ray.

2. Relevant Concepts

  • Angle of incidence (ii): The angle between the incident ray and the normal.
  • Angle of reflection (rr): The angle between the reflected ray and the normal.
  • According to the law of reflection: r=i r = i

3. Analysis and Detail

Given:

  • Angle of incidence i=56i = 56^\circ

From the law of reflection: r=i=56 r = i = 56^\circ

Now, to find the angle between the incident ray and the reflected ray, we calculate: Angle between incident ray and reflected ray=i+r=56+56=112 \text{Angle between incident ray and reflected ray} = i + r = 56^\circ + 56^\circ = 112^\circ

4. Verify and Summarize

  • Both angles are equal as per the law of reflection.
  • The total angle formed between the incident ray and the reflected ray is calculated correctly.

Final Answer

The angle between the incident ray and the reflected ray is 112112^\circ.

This problem has been solved

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