The sum of two-digit number and the number obtained by reversing the order of its digitsis 88. Express this information in linear equation in two variables.
Question
The sum of a two-digit number and the number obtained by reversing the order of its digits is 88.
Express this information in a linear equation in two variables.
Solution
Let's denote the two-digit number as XY, where X is the tens digit and Y is the units digit.
In terms of actual numerical value, this number is equal to 10X + Y (since X is in the tens place and Y is in the units place).
The number obtained by reversing the digits is YX, which is equal to 10Y + X.
According to the problem, the sum of these two numbers is 88. So, we can write this as a linear equation:
(10X + Y) + (10Y + X) = 88
This simplifies to:
11X + 11Y = 88
Dividing through by 11 gives the final equation:
X + Y = 8
So, the linear equation in two variables (X and Y) that represents this information is X + Y = 8.
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