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The sum of two-digit number and the number obtained by reversing the order of its digitsis 88. Express this information in linear equation in two variables.

Question

The sum of a two-digit number and the number obtained by reversing the order of its digits is 88.

Express this information in a linear equation in two variables.

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Solution

Let's denote the two-digit number as XY, where X is the tens digit and Y is the units digit.

In terms of actual numerical value, this number is equal to 10X + Y (since X is in the tens place and Y is in the units place).

The number obtained by reversing the digits is YX, which is equal to 10Y + X.

According to the problem, the sum of these two numbers is 88. So, we can write this as a linear equation:

(10X + Y) + (10Y + X) = 88

This simplifies to:

11X + 11Y = 88

Dividing through by 11 gives the final equation:

X + Y = 8

So, the linear equation in two variables (X and Y) that represents this information is X + Y = 8.

This problem has been solved

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