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A particle undergoes simple harmonic motion having time-period T. The time taken 3/8th oscillation is-

Question

A particle undergoes simple harmonic motion having time-period T. The time taken for 38 \frac{3}{8} th oscillation is-

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Solution

1. Break Down the Problem

We need to find the time taken for 38\frac{3}{8} of an oscillation of a particle undergoing simple harmonic motion (SHM) with a time period TT.

2. Relevant Concepts

The time period TT is the time taken for one complete oscillation. To find the time for any fraction of the oscillation, we can use the relationship: Time for xT=x1T \text{Time for } \frac{x}{T} = \frac{x}{1} \cdot T where xx is the fraction of the oscillation.

3. Analysis and Detail

In our case, we need to calculate the time for 38\frac{3}{8} of the oscillation. Therefore: Time taken for 38 oscillation=38T \text{Time taken for } \frac{3}{8} \text{ oscillation} = \frac{3}{8} \cdot T

4. Verify and Summarize

Now, substituting the value into the formula gives us the required time for 38\frac{3}{8} of an oscillation.

Final Answer

The time taken for 38\frac{3}{8} of the oscillation is 3T8\frac{3T}{8}.

This problem has been solved

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