Knowee
Questions
Features
Study Tools

Let ๐‘„โˆ— be the set of non-zero rational numbers and * be the binary operation on Q definedby ๐‘Ž โˆ— ๐‘ = ๐‘Ž๐‘/3. Prove that ๐‘„โˆ— is group under *.

Question

Let Qโˆ— Q^* be the set of non-zero rational numbers and โˆ— * be the binary operation on Q Q defined by aโˆ—b=ab3 a * b = \frac{ab}{3} . Prove that Qโˆ— Q^* is a group under โˆ— * .

๐Ÿง Not the exact question you are looking for?Go ask a question

Solution

To prove that Q* is a group under *, we need to show that it satisfies the four group axioms: closure, associativity, identity, and invertibility.

  1. Closure: For any two elements a, b in Q*, ab = ab/3 is also in Q because the product and division of non-zero rational numbers is also a non-zero rational number.

  2. Associativity: For any three elements a, b, c in Q*, we need to show that (ab)c = a(bc). (ab)c = (ab/3)c = abc/3^2 a(bc) = a(bc/3) = abc/3^2 Therefore, (ab)c = a(bc), so * is associative.

  3. Identity: We need to find an element e in Q* such that for every element a in Q*, ae = ea = a. Let's try e = 3. a3 = a3/3 = a and 3a = 3a/3 = a. So, e = 3 is the identity element.

  4. Invertibility: For each element a in Q*, there must exist an element b in Q* such that ab = ba = e. Let's try b = 1/a. Then ab = a(1/a) = a/a = 1 and b*a = (1/a)*a = a/a = 1. So, b = 1/a is the inverse of a.

Therefore, Q* is a group under *.

This problem has been solved

Similar Questions

Let ๐บ = [๐‘Ž 00 0] : ๐‘Ž ๐‘–๐‘  ๐‘Ž ๐‘›๐‘œ๐‘› โˆ’ ๐‘ง๐‘’๐‘Ÿ๐‘œ ๐‘Ÿ๐‘’๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ } . hho that ๐บ is a oommutativegroup under multiplioation

The group of real numbers under multiplication has the identity element:a.-1b.0c.1d.โˆž

"For any three real numbers x, y, and z, xโˆ™(yโˆ™z)=(xโˆ™y)โˆ™z"ย is one of the condition in what binary operation?

Question: 25 out of 502 markReview LaterAdditive inverse and multiplicative inverse of a rational number 2/3 are respectively, X and Y, then:

8. Let ๐บ be a group ith identity ๐‘’ suoh that ๐‘Ž2 = ๐‘’ for all ๐‘Ž โˆˆ ๐บ, then ๐บ is abelian.

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.