methylation of 10g of benzene gives 9.2g of toluene calculate the percentage yeild of toluene

First, we need to calculate the theoretical yield of toluene.

1. Calculate the molar mass of benzene (C6H6) and toluene (C7H8).

   Molar mass of benzene = (612.01 g/mol C) + (61.008 g/mol H) = 78.114 g/mol Molar mass of toluene = (712.01 g/mol C) + (81.008 g/mol H) = 92.138 g/mol

2. Calculate the number of moles of benzene used.

   Moles of benzene = mass / molar mass = 10 g / 78.114 g/mol = 0.128 moles

3. The reaction of benzene with methyl chloride is a 1:1 reaction, so the number of moles of toluene produced should also be 0.128 moles.

4. Calculate the theoretical mass of toluene produced.

   Mass of toluene = moles * molar mass = 0.128 moles * 92.138 g/mol = 11.79 g

Now, we can calculate the percentage yield.

5. Percentage yield = (actual yield / theoretical yield) * 100%

   Percentage yield = (9.2 g / 11.79 g) * 100% = 78.0%

So, the percentage yield of toluene is 78.0%.