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swerAn expression involving byte, int, and literal numbers is promoted to which of these?Optionsintbytelongfloat

Question

An expression involving byte, int, and literal numbers is promoted to which of these?

Options:

  • int
  • byte
  • long
  • float
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Solution

Break Down the Problem

  1. Identify the types involved in the expression: byte, int, and literal numbers.
  2. Understand the rules of promotion in Java or similar programming languages regarding these types.

Relevant Concepts

  1. In Java, when performing operations involving different numeric types, the smaller types are typically promoted to larger types.
  2. The promotion hierarchy in Java is as follows:
    • byte → short → int → long → float → double

Analysis and Detail

  1. Since the types mentioned are byte and int:

    • A byte is promoted to int when involved in mathematical expressions.
    • If the literal number is a whole number within the range of int, it defaults to int.
  2. Therefore, when byte, int, and a literal number are combined in an expression, the promotion follows the path to the largest type involved, which would be:

    • Both byte and the literal number would be promoted to int before evaluating.

Verify and Summarize

Since byte is promoted to int, and the literal is typically treated as an int, the overall type of the expression will also be int. None of the other data types (long, float) are applicable unless specified by a floating-point literal or a larger numeric in the operation.

Final Answer

The expression is promoted to int.

This problem has been solved

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