swerAn expression involving byte, int, and literal numbers is promoted to which of these?Optionsintbytelongfloat
Question
An expression involving byte, int, and literal numbers is promoted to which of these?
Options:
- int
- byte
- long
- float
Solution
Break Down the Problem
- Identify the types involved in the expression: byte, int, and literal numbers.
- Understand the rules of promotion in Java or similar programming languages regarding these types.
Relevant Concepts
- In Java, when performing operations involving different numeric types, the smaller types are typically promoted to larger types.
- The promotion hierarchy in Java is as follows:
- byte → short → int → long → float → double
Analysis and Detail
-
Since the types mentioned are byte and int:
- A
byte
is promoted toint
when involved in mathematical expressions. - If the literal number is a whole number within the range of
int
, it defaults toint
.
- A
-
Therefore, when
byte
,int
, and a literal number are combined in an expression, the promotion follows the path to the largest type involved, which would be:- Both
byte
and the literal number would be promoted toint
before evaluating.
- Both
Verify and Summarize
Since byte
is promoted to int
, and the literal is typically treated as an int
, the overall type of the expression will also be int
. None of the other data types (long, float) are applicable unless specified by a floating-point literal or a larger numeric in the operation.
Final Answer
The expression is promoted to int.
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