What would be the size of the following union declaration? (Assuming size of double = 8, size of int = 4, size of char = 1)

Break Down the Problem

1. Identify the data types in the union.

   • The union contains a double, an int, and a char.

2. Determine the size of each data type.

   • Size of double = 8 bytes
   • Size of int = 4 bytes
   • Size of char = 1 byte

3. Consider alignment and padding.

   • Most systems align data types to their size, so the largest data type will determine the total size of the union.

Relevant Concepts

• The size of a union in C/C++ is determined by the size of its largest member, including any necessary padding for alignment.

Analysis and Detail

1. The largest type in the union is double, which has a size of 8 bytes.
2. Although int (4 bytes) and char (1 byte) could occupy less space individually, the union's size must accommodate the largest member while respecting alignment.

Verify and Summarize

• The union, therefore, will have a size equal to the size of the largest data member, which is the double type at 8 bytes.

Final Answer

The size of the union is 8 bytes.