In a series circuit, the total resistance increases when an additional light bulb is added. This change affects the current flowing through the circuit because, according to Ohm's Law ($I = \frac{V}{R}$), as resistance ($R$) increases, the overall current ($I$) decreases given a constant voltage ($V$).

As the current decreases, each lightbulb receives less electrical current, resulting in less brightness. Therefore, if one light bulb is added to a series circuit that already contains a light bulb, both bulbs will dim because they share the reduced current.

### Final Answer
True.

Question

In a series circuit, the total resistance increases when an additional light bulb is added. This change affects the current flowing through the circuit because, according to Ohm's Law ($I = \frac{V}{R}$), as resistance ($R$) increases, the overall current ($I$) decreases given a constant voltage ($V$).

As the current decreases, each lightbulb receives less electrical current, resulting in less brightness. Therefore, if one light bulb is added to a series circuit that already contains a light bulb, both bulbs will dim because they share the reduced current.

### Final Answer
True.

Knowee AI · Accepted Answer

In a series circuit, the total resistance increases when an additional light bulb is added. This change affects the current flowing through the circuit because, according to Ohm's Law ($I = \frac{V}{R}$), as resistance ($R$) increases, the overall current ($I$) decreases given a constant voltage ($V$).

As the current decreases, each lightbulb receives less electrical current, resulting in less brightness. Therefore, if one light bulb is added to a series circuit that already contains a light bulb, both bulbs will dim because they share the reduced current.

### Final Answer
True.

In a series circuit, the already existing lightbulb dims when another light bulb is added*1 pointTrueFalse

Question

In a series circuit, the already existing lightbulb dims when another light bulb is added.

Solution

Final Answer

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