Let y=loge(1−x21+x2),−1<x<1. Then at x=12, the value of 225(y′−y′′) is equal to

Question

Let y=loge(1−x21+x2),−1<x<1. Then at x=12, the value of 225(y′−y′′) is equal to
🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To solve this problem, we need to find the first and second derivatives of the given function, and then substitute x = 1/2 into these derivatives.

Step 1: Differentiate y with respect to x The given function is y = loge(1−x^2/1+x^2). The derivative of y with respect to x, denoted as y', can be fou Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob

Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solv

This problem has been solved

Similar Questions

Let y=loge(1−x21+x2),−1<x<1. Then at x=12, the value of 225(y′−y′′) is equal to

Let the area of the region {(x,y):0≤x≤3,0≤y≤ min{x2+2,2x+2}} be A. Then 12 A is equal to ______

Let x and y be positive real numbers such that x2 + y2 = 1 and (3x – 4x3)(3y – 4y3) = . Then x + y is , then k is

Let f(x)=2x−x2,x∈R. If m and n are respectively the number of points at which the curves y=f(x) and y=f′(x) intersects the x-axis, then the value of m+n is

Given that y = 3 for x = 1 and x varies inversely as , then find the value of x for y =12.

1/3