Write the balanced acid-base reactions and calculate the pH of the followingaqueous solutions:i) H2 S 0.01 M (Ka1 (H2 S) = 9.5×10-8 ; Ka2 (HS-) = 1.3×10-13 )
Question
Solution 1
The first step is to write the balanced acid-base reactions for H2S.
H2S is a diprotic acid, meaning it can donate two protons (H+). The two ionization steps are:
- H2S ⇌ H+ + HS- (Ka1 = 9.5×10^-8)
- HS- ⇌ H+ + S^2- (Ka2 = 1.3×10^-13)
Next, we calculate the pH of the 0.01 M H2S solution.
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