# packet of sweets is distributed among A, B, C, D in the proportion of 6:8:5:4. If B gets 10 sweets more than D then what is A’s share?Options :16171518

## Question

## Solution 1

The total ratio of the sweets distributed among A, B, C, and D is 6:8:5:4.

Step 1: Add up all the parts of the ratio. 6 (for A) + 8 (for B) + 5 (for C) + 4 (for D) = 23 parts in total.

Step 2: We know that B gets 10 sweets more than D. The ratio tells us that B gets 8 parts and D gets 4 parts. S Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

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