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What is the variance of a random sample of size 5 that is taken with replacement from a population with mean = 15 and  variance = 10?

Question

What is the variance of a random sample of size 5 that is taken with replacement from a population with mean = 15 and variance = 10?

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Solution

1. Break Down the Problem

To find the variance of a random sample size of 5 drawn with replacement from a population, we need to understand how the sample variance relates to the population variance.

2. Relevant Concepts

The variance of a random sample drawn from a population with known variance can be calculated using the formula for the variance of the sample mean: σxˉ2=σ2n \sigma^2_{\bar{x}} = \frac{\sigma^2}{n} where:

  • σxˉ2 \sigma^2_{\bar{x}} is the variance of the sample mean,
  • σ2 \sigma^2 is the population variance,
  • n n is the sample size.

3. Analysis and Detail

Given:

  • Population variance (σ2 \sigma^2 ) = 10
  • Sample size (n n ) = 5

We can plug these values into the formula: σxˉ2=105 \sigma^2_{\bar{x}} = \frac{10}{5}

Calculating this gives: σxˉ2=2 \sigma^2_{\bar{x}} = 2

4. Verify and Summarize

We calculated the variance of the sample mean, which is 2. This indicates how much the sample mean xˉ \bar{x} varies from the population mean.

Final Answer

The variance of the random sample of size 5 is 2 2 .

This problem has been solved

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