When lead nitrate reacts with potassium iodide, yellow precipitate ofPbI2 is formedKNO3 is formedPb(NO3)2 is formedPbIO3 is formed
Question
When lead nitrate reacts with potassium iodide, the following products are formed:
- Yellow precipitate of PbI2
- KNO3 is formed
- Pb(NO3)2 is formed
- PbIO3 is formed
Solution
When lead nitrate (Pb(NO3)2) reacts with potassium iodide (KI), a double displacement reaction occurs. Here's the step by step process:
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Identify the reactants which are lead nitrate and potassium iodide.
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Write down the chemical reaction: Pb(NO3)2 + 2KI → PbI2 + 2KNO3
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In this reaction, th
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