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Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?Question 18Answera.25200b.22500c.Noned.22220

Question

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

Question 18
Answer

  • a. 25200
  • b. 22500
  • c. None
  • d. 22220
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Solution

To solve this problem, we need to use the concept of combinations in probability.

Step 1: Select 3 consonants out of 7 This can be done in 7C3 ways. The formula for combinations is nCr = n! / r!(n-r)!. Here, n is the total number of items, and r is the number of items to choose. So, 7C3 = 7! / 3!(7-3)! = 35 ways.

Step 2: Select 2 vowels out of 4 This can be done in 4C2 ways. So, 4C2 = 4! / 2!(4-2)! = 6 ways.

Step 3: Arrange the selected consonants and vowels We have 5 letters (3 consonants and 2 vowels), which can be arranged in 5! = 120 ways.

Step 4: Multiply the results of steps 1, 2, and 3 The total number of words is 35 (from step 1) * 6 (from step 2) * 120 (from step 3) = 25200.

So, the answer is a. 25200.

This problem has been solved

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