What would be the product after treating acetaldehyde with K2Cr2O7 in H2SO4?Question 6Answera.Ethanoic acidb.Acetonec.Acetald.Ethanol
Question
What would be the product after treating acetaldehyde with K2Cr2O7 in H2SO4?
- a. Ethanoic acid
- b. Acetone
- c. Acetaldehyde
- d. Ethanol
Solution
The product of treating acetaldehyde (CH3CHO) with potassium dichromate (K2Cr2O7) in sulfuric acid (H2SO4) would be ethanoic acid (CH3COOH).
Here's the step-by-step process:
-
Potassium dichromate (K2Cr2O7) in sulfuric acid (H2SO4) is a strong oxidizing agent.
-
When acetaldehyde (CH3CHO) is treated with this oxidizing agent, the aldehyde group (-CHO) gets oxidized to a carboxylic acid group (-COOH).
-
Therefore, acetaldehyde (CH3CHO) gets converted to ethanoic acid (CH3COOH).
So, the correct answer is a. Ethanoic acid.
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