When the switch is open, the data measured are listed below. Complete the table.(3 marks)Lamp L Lamp M Lamp NCurrent 0.3 AVoltage 1.5 V 0 V

To complete the table based on the given measurements when the switch is open, we can analyze the data for each lamp provided.

1. Breakdown of the Problem

1. We will focus on the current and voltage data for each lamp.
2. Lamp N is showing a voltage of 0 V, which indicates it may not be functional or connected in a way that allows current to pass through.

2. Relevant Concepts

1. Ohm’s Law states that $V = I \times R$, where:
   • $V$ is voltage,
   • $I$ is current,
   • $R$ is resistance.
2. If we know the current and voltage for Lamp L and Lamp M, we can infer their resistance.

3. Analysis and Detail

1. For Lamp L:

   • Current $I_L = 0.3 \, \text{A}$
   • Voltage $V_L = 1.5 \, \text{V}$
   • Resistance $R_L = \frac{V_L}{I_L} = \frac{1.5 \, \text{V}}{0.3 \, \text{A}} = 5 \, \Omega$

2. For Lamp M (voltage not specified):

   • Let’s assume Lamp M has a voltage of $V_M$ to be found.
   • The current for Lamp M is not given, but its voltage is 0 V. Therefore, we conclude:
   • Current $I_M = 0 \, \text{A}$ (because if $V_M = 0 \, \text{V}$, then no current flows).

3. For Lamp N:

   • Voltage $V_N = 0 \, \text{V}$
   • Since the voltage is 0, the current is also $I_N = 0 \, \text{A}$.

4. Verify and Summarize

• We confirmed using Ohm’s Law that the following is true:
  • Lamp L has a resistance of $5 \, \Omega$.
  • Both Lamp M and Lamp N do not have current flowing through them since their voltages are 0 V.
• Therefore, the completed table should look like this:

Final Answer