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The digit in unit’s place of the product (2153)^167 is:radio_button_unchecked1radio_button_unchecked3radio_button_unchecked7radio_button_unchecked9

Question

The digit in unit’s place of the product (2153)^167 is:

  • radio_button_unchecked 1
  • radio_button_unchecked 3
  • radio_button_unchecked 7
  • radio_button_unchecked 9
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Solution

To find the digit in the unit's place of the product (2153)^167, we only need to consider the last digit of the base number, which is 3 in this case.

The pattern of the last digit of the powers of 3 is as follows:

3^1 = 3 3^2 = 9 3^3 = 7 3^4 = 1 3^5 = 3 3^6 = 9 3^7 = 7 3^8 = 1 ...

As you can see, the pattern repeats every 4 powers.

So, to find the last digit of (2153)^167, we need to find the remainder when 167 is divided by 4.

167 divided by 4 gives a quotient of 41 and a remainder of 3.

Therefore, the last digit of (2153)^167 is the same as the last digit of 3^3, which is 7.

So, the digit in the unit's place of the product (2153)^167 is 7.

This problem has been solved

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