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The length of a rectangle, whose perimeter is 12 2 /5m, is twice its breadth. Find its area

Question

The length of a rectangle, whose perimeter is 12 2 /5m, is twice its breadth. Find its area.

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Solution

Step 1: Let's denote the breadth of the rectangle as x. Given that the length is twice the breadth, we can denote the length as 2x.

Step 2: The formula for the perimeter of a rectangle is 2(length + breadth). Substituting the given perimeter and our denotations for length and breadth, we get:

12 2/5 = 2(2x + x)

Step 3: Simplify the equation:

12 2/5 = 2(3x)

Step 4: Solve for x:

x = (12 2/5) / (2*3) = 2 1/15 m

Step 5: Now that we have the breadth, we can find the length by multiplying by 2:

length = 2 * 2 1/15 = 4 2/15 m

Step 6: The area of a rectangle is given by the formula length * breadth. Substituting our values, we get:

Area = (4 2/15) * (2 1/15) = 8 7/225 m^2

So, the area of the rectangle is 8 7/225 square meters.

This problem has been solved

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