Write the ionic equation for the following reaction: KOH(aq) + HCl (aq) → KCl (aq) + H2O(l)

Question

Write the ionic equation for the following reaction:

$\text{KOH(aq)} + \text{HCl (aq)} \rightarrow \text{KCl (aq)} + \text{H}_2\text{O(l)}$

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Solution

Sure, here is the ionic equation for the reaction:

Step 1: Write the balanced molecular equation: KOH(aq) + HCl(aq) → KCl(aq) + H2O(l)

Step 2: Write the ionic equation. The ionic equation shows all of the particles as they exist in solution. If the substance is aqueous, it will dissociate into ions. If it is a solid, liquid, or gas, it will not dissociate and will stay as is:

K+(aq) + OH-(aq) + H+(aq) + Cl-(aq) → K+(aq) + Cl-(aq) + H2O(l)

Step 3: Write the net ionic equation. The net ionic equation is derived from the ionic equation, and it eliminates the spectator ions (ions that appear on both sides of the equation). In this case, the spectator ion is K+ and Cl-:

OH-(aq) + H+(aq) → H2O(l)

So, the net ionic equation for the reaction of KOH(aq) and HCl(aq) is OH-(aq) + H+(aq) → H2O(l).

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Write the ionic equation for the following reaction: KOH(aq) + HCl (aq) → KCl (aq) + H2O(l)

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