Reverse last k digits of the given numberInput Format:Accept two integer  as inputOutput Format:print the reversed k digits

Here is a step-by-step solution in Python:

1. First, we need to accept two integers as input. Let's call the first integer num and the second integer k.

num = int(input("Enter the number: "))
k = int(input("Enter the number of digits to reverse: "))

2. Next, we need to extract the last k digits from num. We can do this by converting num to a string, slicing the last k characters, and then converting back to an integer.

last_k_digits = int(str(num)[-k:])

3. Now, we need to reverse these k digits. We can do this by converting last_k_digits to a string, reversing the string using slicing, and then converting back to an integer.

reversed_digits = int(str(last_k_digits)[::-1])

4. Finally, we need to replace the last k digits of num with reversed_digits. We can do this by subtracting last_k_digits from num, and then adding reversed_digits.

num = num - last_k_digits
num = num + reversed_digits

5. Print the final result.

print("The number after reversing the last k digits is: ", num)

Please note that this solution assumes that num has at least k digits. If num has fewer than k digits, the program will reverse all the digits of num.